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1.6X=X^2+13X
We move all terms to the left:
1.6X-(X^2+13X)=0
We get rid of parentheses
-X^2+1.6X-13X=0
We add all the numbers together, and all the variables
-1X^2-11.4X=0
a = -1; b = -11.4; c = 0;
Δ = b2-4ac
Δ = -11.42-4·(-1)·0
Δ = 129.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11.4)-\sqrt{129.96}}{2*-1}=\frac{11.4-\sqrt{129.96}}{-2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11.4)+\sqrt{129.96}}{2*-1}=\frac{11.4+\sqrt{129.96}}{-2} $
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